Start learning 50% faster. Sign in now
Let the total amount invested be ₹x. Amount invested in Scheme A = (3/5)x, and in Scheme B = (2/5)x. Interest from Scheme A = [(3/5)x * 12 * 2] / 100 = (72/500)x. Interest from Scheme B = [(2/5)x * 10 * 2] / 100 = (40/500)x. Total interest = (72/500)x + (40/500)x = 112x / 500. Given total interest = ₹3024. 112x / 500 = 3024 x = (3,024 * 500) / 112 = ₹13500 Correct Option: c
If secθ + tanθ = 3+√10, then the value of sinθ+cosθ is
If sec(2A + B) = 2 and cos(A + B) = (1/√2) , find the value of {sec 2B + tan (A + B) } given that 0o < A, B < 90o
Two points P and Q are at the distance of x and y (where y > x) respectively from the base of a building and on a straight line. If the angles of elevat...
If P, Q, R, S are the vertex of a cyclic quadrilateral. Find the value of
`1/sec p` +`1/sec q` +`1/sec r` +`1/sec s`
...From a point on the ground, the angle of elevation of the top of a building is 45°. After walking 10 meters towards the building, the angle of elevatio...
Find the simplified value of the following expression if a = 30o
[(sin2a + cos2a} ÷ seca × sina ÷ cosa]
...Calculate the value of sec75o
If sin (2x + 50) o = cos (2y - 50) o, such that, 0o < x + y < 90o, then find the value of tan(x + y) .
ABC is an isosceles triangle where AB = AC which is circumscribed about a circle. If P is the point where the circle touches the side BC, then which of ...
If tan θ + cot θ = 2 where 0 < θ < 90 ; find the value of tan30 θ + cot 29 θ.