Let the total amount invested be ₹x. Amount invested in Scheme A = (3/5)x, and in Scheme B = (2/5)x. Interest from Scheme A = [(3/5)x * 12 * 2] / 100 = (72/500)x. Interest from Scheme B = [(2/5)x * 10 * 2] / 100 = (40/500)x. Total interest = (72/500)x + (40/500)x = 112x / 500. Given total interest = ₹3024. 112x / 500 = 3024 x = (3,024 * 500) / 112 = ₹13500 Correct Option: c
A circular coil of wire consisting of 120 turns, each of radius 12 cm carries a current of 0.30 A. What is the magnitude of the magnetic field B at the ...
A rocket with a lift-off mass 10,000 kg is blasted upwards with an initial acceleration of 5.0 m s–2. Calculate the initial thrust (force) ...
A piece of ice is floating in water kept in a beaker. When all the ice melts the level of water will -
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