Question
A man invested a certain amount in two schemes, A and B,
in the ratio 3:2. Scheme A offers 12% annual simple interest, and Scheme B offers 10% annual simple interest. After 2 years, the total interest earned from both schemes is ₹3,024. What was the total amount invested?Solution
Let the total amount invested be ₹x. Amount invested in Scheme A = (3/5)x, and in Scheme B = (2/5)x. Interest from Scheme A = [(3/5)x * 12 * 2] / 100 = (72/500)x. Interest from Scheme B = [(2/5)x * 10 * 2] / 100 = (40/500)x. Total interest = (72/500)x + (40/500)x = 112x / 500. Given total interest = ₹3024. 112x / 500 = 3024 x = (3,024 * 500) / 112 = ₹13500 Correct Option: c
Find the wrong no in the given number series.
2, 4, 8, 16, 33, 64
Find the wrong number in given number series.
2372, 2356, 2320, 2256, 2156, 2048.
- Find the wrong number in the given number series.
25, 34, 18, 34, 9, 46 112, 119, 133, 154, 180, 217
135, 148, 109, 174, 87, 200Â
128, 173, 196, 189, 176, 133
Find the wrong number in the given number series.
7, 9, 16, 12, 25, 15, 365, 13, 41, 185, 1111, 8149
Find the wrong number in the given number series.
102, 124, 160, 212, 289, 410
 16, 19, 28, 44, 76, 140, 268
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