A gets 30% of the full marks in an exam and fails by 90 marks. B gets 36% of the full marks in the same exam and he also fails by 72 marks. What is the minimum percentage of marks a student should obtain to pass the exam?
Let maximum marks = 100x ∴ 30x + 90 = 36x + 72 => 6x = 18 => x = 3 ∴ Max marks = 100x = 300 ∴ Minimum percentage marks to be pass = {[(30×3) + 90]/300} × 100 = 60%
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