A gets 30% of the full marks in an exam and fails by 90 marks. B gets 36% of the full marks in the same exam and he also fails by 72 marks. What is the minimum percentage of marks a student should obtain to pass the exam?
Let maximum marks = 100x ∴ 30x + 90 = 36x + 72 => 6x = 18 => x = 3 ∴ Max marks = 100x = 300 ∴ Minimum percentage marks to be pass = {[(30×3) + 90]/300} × 100 = 60%
If a nine-digit number 389x6378y is divisible by 72, then the value of √(6x + 7y) will be∶
110 ÷ 5.5 + (?)3 ÷ 12 = 20(2/3)
√? = 120 - 102 + ∛125
(√2704 x 55)/(245 + 120) = ?
26 X √25 + 15 - 80% of 120 = ?2
42% of 400 + 38% of 800 + ?2 = 728
3/8 of 720 ÷ 15 + 12 = √?
121/? = ?/144
25% of 12% of 1600 + 112 = ? × 4
‘A’ and ‘B’ invested Rs. 5000 and Rs. 4200, respectively in a business, together. After 7 months, ‘A’ withdrew 25% of his initial investment...