Question
A gets 36% of the full marks in an exam and fails by 90
marks. B gets 39% of the full marks in the same exam and he also fails by 75 marks. What is the minimum percentage of marks a student should obtain to pass the exam?Solution
Let maximum marks = 100x ∴ 36x + 90 = 39x + 75 => 3x = 15 => x = 5 ∴ Max marks = 100x = 500 ∴ Minimum percentage marks to be pass = {[(36×5) + 90]/500} × 100 = 54%
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