Question
A gets 36% of the full marks in an exam and fails by 90
marks. B gets 38% of the full marks in the same exam and he also fails by 72 marks. What is the minimum percentage of marks a student should obtain to pass the exam?Solution
Let maximum marks = 100x ∴ 36x + 90 = 38x + 72 => 2x = 18 => x = 9 ∴ Max marks = 100x = 900 ∴ Minimum percentage marks to be pass = {[(36×9) + 90]/900} × 100 = 46%
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