Two numbers are less than a third number by 25% and 31% respectively. Find the percent by which the second number is less than the first.
Let the third number be 100. Then, first number will be = 100 – 25 = 75 And the second number will be = 100 – 31 = 69 Required % = [(75 – 69)/75]×100 = 8%
{(84.04% of 649.95 + 27.92 × 13.13) – 21.11 × ?} = 763.35
2470.03 ÷ 64.98 x 39.9 = ? + 20.32
? = 54.89 × 270.08 ÷ 135.17 + 464.35 ÷ 29.03
1299.99 ÷ 20.21 = ? + 325.985 - (180 ÷ 6 × 24.03)
(899.117 + 1.1121) X 72.731 = ? + 49.95 X 64.78 + 29.50
837.04 × 4.02 + 40.04% of 3049.98 – 3667.82 = ? 2 – 60.87
(5.013 – 30.04) = ? + 11.98% of 4799.98
[(120.96 × 12.09) ÷ ?] ÷ 6 = 19.96% of 55.07