Question
The monthly income of a person is Rs.25000 from which
he spends 20% on rent, 10% of remaining on food and 20% of remaining on clothing. The remaining amount, he shares between his son and daughter in the ratio of 5:4. Find the difference between amount spent on rent and share of his daughter.Solution
Let monthly income be 100x. Spent on rent = 100x × (20/100) = 20x Spent on food = (100x − 20x) × (10/100) = 8x Spent on clothing = (100x − 20x − 8x) × (20/100) = 14.4x Remaining amount = 100x − 20x − 8x − 14.4x = 57.6x Share of son = 57.6x × (5/9) = 32x Share of daughter = 57.6x − 32x = 25.6x Required difference = 25.6x − 20x = 5.6x => 5.6x × (25000/100x)  = Rs. 1400
126Â Â Â Â Â 130 Â Â Â Â Â 114 Â Â Â Â Â Â 150Â Â Â Â Â 82 Â Â Â Â Â 186 Â Â Â Â Â 42
...4, 11, 24, 46, 74, 109
Find the wrong number in the given number series.
12, 24, 72, 216, 1440, 8640
5, 6, 8, 16, 38, 158
3, 6, 18, 90, 630, 5670
Find the wrong number in the given number series.
24, 120, 720, 5040, 40320, 362881
3Â Â Â 4Â Â Â 18Â Â Â Â 72Â Â Â Â 360Â Â Â Â Â 2160Â Â Â
100, 164, 740, 3044, 9444, 20320
556, 547, 483, 458, 242, 196Â
Find the wrong number in the given number series.
3, 4, 10, 33, 136, 680
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