Question
In a bio gas plant the population of yeast bacteria
increases at a rate of 19% per annum but there is an additional annual increase of 1% in population due to various other inputs in the system. The percentage increase in the yeast population after 2 years is:Solution
The population of bacteria increases by 19% per annum and 1% due to additional factors, so every year, there is a net increase of 20% in yeast population. Let the population at present be x. Population after 2 years = x × 120/100 × 120/100 = 144x/100 = 1.44x % increase in population = [(1.44x - x)/x] × 100 = 44

30 of 20 - 40 + 182 - 23 × ? = 83Â
[(4/3) + (5/6)] of 378 = ?
- What will come in the place of question mark (?) in the given expression?
40% of (320 ÷ 4) + 2² X 25 = ? + 42 Find the value of 'p' in the given expression: 15 of 6 ÷ p x 4 = 30.
What will come in the place of question mark (?) in the given expression?
59.92 × 15.11 + √4224 = ? + 144.9Â
What will come in place of (?) in the given expression.
25% of 160 + 15% of 200 = ??% of 740 – 8% of 650 = 7.2
(64/25)? × (125/512)?-1 = 5/8
- What will come in the place of question mark (?) in the given expression?
62.5% of 120 + ? = (720 + 90) ÷ √36