Seven years ago, the ratio of the ages of A and B was 4: 5. Eight years hence, the ratio of the ages of A and B will be 9:10. What is the sum of their present ages in years?
Seven years ago the ratio of ages of A and B = 4x : 5x Ratio of Present ages of A and B = 4x + 7 : 5x + 7 After 8 years the ratio of ages of A and B, ⇒ (4x + 7 + 8) : (5x + 7 + 8) = 9 : 10 ⇒ 40x + 150 = 45x + 135 ⇒ 5x = 15 ⇒ x = 3 Sum of present ages of A and B = (4 × 3 + 7) + (5 × 3 + 7) = 41 years ∴ The sum of present ages of A and B is 41 years.
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 27x6- 152x3+ 125 = 0
II. 216y6- 91y3+ 8 = 0
I.√(3x-17)+ x=15
II. y+ 135/y=24
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0
