A spent 36% and 25% of his monthly salary on food and rent, respectively. Of the remaining amount, he gave 15% and 10% to his mother and brother, respectively. Find the amount spent by him on food, if the difference between the amount received by his brother and the amount spent on rent is Rs. 2110.
Let the monthly salary of A be Rs. ‘x’ Amount spent on food = Rs. 0.36x Amount spent on rent = Rs. 0.25x Amount received by brother = (x – 0.36x – 0.25x) × 0.10 = 0.039x So according to question: => 0.25x – 0.039x = 2110 => 0.211x = 2110 => x = 10000 So, the amount spent on food = 0.36 × 10000 = Rs. 3600
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 27x6- 152x3+ 125 = 0
II. 216y6- 91y3+ 8 = 0
I.√(3x-17)+ x=15
II. y+ 135/y=24
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0