Question
The sum of the monthly incomes of βAβ, βBβ and
βCβ is Rs. 95000 which is 4 times the monthly income of βCβ. If βAβ spends 25% of his income while βBβ spends 80% of his income and the sum of their savings is Rs. 18900, then find the savings of βAβ.Solution
Given:- A+B+C=95,000 A+B+C=4C, So A+B=3C A's savings = 75% of B's savings = 20% of B, and their combined savings = Rs. 18,900. Therefore, A+B+C=4C, we find C=23,750. Substitute C=23,750 into A+B=3C, So A+B=71,250. Use the savings equation 0.75A+0.20B=18,900, and substitute B=71,250βA. Solve the system of equations to get A=8,454.55. Hence, Savings of A's savings = 75% of A = 0.75Γ8,454.55 = 6,340.91.
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