A and B together have total of Rs.4000 out of which they donated 20% to the orphanage school. The remaining amount is to be then redistributed between them in such a manner that A gets 50% more amount than B. If the amount received by A is Rs.2X, then find the value of [(X/12) + 8].
Let the amount received by B be Rs.P. Therefore, amount received by A = 1.50 x P = Rs.1.5P According to the question, => (P + 1.5P) = 4000 x 0.8 => 2.5P = 3200 => P = 1280 Share of A = 3200 – 1280 = Rs.1920 So, 2X = 1920 => X = 960 Required value = [(X/12) + 8] = 80 + 8 = 88
Quantity I: The price of rice is decreased by 30%, by how much % the consumption is increase so that the expenditure will decreased by 10%?
Quant...
I. 4x2+ 25x + 36 =0
II. 2y2+ 5y + 3 = 0
I. 2(x+2)+ 2(-x)=5
II. (1/(y+1)+ 1/(y+5))=(1/(y+2)+ 1/(y+4))
I. 56x² - 99x + 40 = 0
II. 8y² - 30y + 25 = 0
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
I. 2 x ² + x – 1 = 0
II. 2 y ² - 3 y + 1 = 0
...I. x2 – 18x + 81 = 0
II. y2 – 3y - 28 = 0
I. 144x² - 163x - 65 = 0
II. 91y² - 128y -48 = 0
I. 5x + 2y = 31
II. 3x + 7y = 36
I. 5x + y = 37
II. 4y+ x = 15
