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Let the amount received by B be Rs.P. Therefore, amount received by A = 1.40 x P = Rs.1.4P According to the question, => (P + 1.4P) = 5000 x 0.90 => 2.4P = 4500 => P = 1875 Share of A = 4500 – 1875 = Rs.2625 So, 3X = 2625 => X = 875 Required value = [(X/5) + 10] = 175 + 10 = 185
18 × √225 + 378 ÷ √441 = ? × 9
x= √(4 × ∛(16 × √(4 × ∛(16 ×…… ∝)) ) )
√? + √1296 + √729 = 464/4
Evaluate: (768÷16)×(125÷25)−(81÷9)×12
15.8% of 9000 + 20.4% of 7500 = 30% of ?
`(450 -: ?)/(2.5 xx 1.2)` = 250
(15 × 16) + 242= ? × 16
(43)² - (28)² + (32)² = ?% of 2500
Find the HCF of 15x2 + 8x – 12, 3x² + x – 2, 3x² - 2x, 9x² - 12x + 4