A and B together have total of Rs.6000 out of which they donated 20% to the orphanage school. The remaining amount is to be then redistributed between them in such a manner that A gets 50% more amount than B. If the amount received by A is Rs.2X, then find the value of [(X/12) + 10].
Let the amount received by B be Rs.P. Therefore, amount received by A = 1.50 x P = Rs.1.5P According to the question, => (P + 1.5P) = 6000 x 0.80 => 2.5P = 4800 => P = 1920 Share of A = 4800 – 1920 = Rs.2880 So, 2X = 2880 => X = 1440 Required value = [(X/12) + 10] = 120 + 10 = 130
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