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Let A had Rs.x with him. According to question, => 60% of 25% of x = 192 => 0.15x = 192 => x = 1280 Amount received by B from A = 60% of 1280 = Rs.768
[(sinx – 2sin 3 x)/(2cos 3 x – cosx)] 2 + 1, x ≠45 o , is equal to:
If tanθ = (2/√5), then find the value of cos2 θ
Solve the following trigonometric expression:
If sin θ + cos θ = 1.2, find the value of sin θ. cos θ.
A flagpole stands on top of a building. From a point 50 meters away from the base of the building, the angle of elevation to the top of the building is ...