Question
In a train, 45% of the passengers are females. Out of
total number of passengers, 65% have unreserved tickets out of which 36% are females. How much percent of females have unreserved tickets?Solution
Let the total number of passengers in the train be ‘x’ Therefore, total number of female passengers = 0.45x Number of female passengers who have unreserved tickets = 0.65 × 0.36x = 0.234x Required percentage = (0.234x/0.45x) × 100 = 52%
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
20 × 224 ÷ 16 – 50 = ? + 100
...(49 x ?) / 3.5 + 389 = 627
If a nine-digit number 389x6378y is divisible by 72, then the value of √(6x + 7y) will be∶
- What will come in the place of question mark (?) in the given expression?
(40 ÷ 5 + 56 ÷ 8) X (? - 42) = 120 5/2 of 5/6 of 12/5 of 54 % of 5250 = ?
779 + 136 – 334 = 270 + 121 + ?
(15/8) x [6924 – 2124] + 910 = ? + 190
25639 – 5252 – 3232 = ?
36 x 3.6 ÷ 0.5 ÷ ? = 64