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    Question

    Certain number of students from two schools takes part in an examination. Out of a total of 100 students who participated from ABC school, x% failed in the exam. The number of students in school XYZ are (6x + 10)% more than the number of students in school ABC. 90% of the students who participated from both the school passes the exam. Ther are 217 students from school XYZ who passed the exam. Find out the value of x?

    A 100 Correct Answer Incorrect Answer
    B 50 Correct Answer Incorrect Answer
    C 20 Correct Answer Incorrect Answer
    D 60 Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    Total number of students in school ABC = 100 So, the number of students from school ABC who failed in the exam = x% of 100 = x So, the number of students from school ABC who passed the exams = 100 – x Total number of students from both schoolABC and XYZ = 100 + (110 + 6x) = 210 + 6x So, total students who passed the exam from school XYZ is, 189 + 5.4x – (100 – x) = 6.4x + 89 = 217 6.4x = 128 x = 20 Hence, option c) is the correct answer.

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