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    Question

    The marked price of a jacket and a T-shirt is Rs. (a +

    300) and Rs. (b + 400) respectively. The shopkeeper sold them at a discount of 20% and 25% respectively to 'X' for a total of Rs. 1635. The average value of a and b is 700. If the jackets and the T-shirts are marked up by 20% and 20% above the cost price and they are sold at double the discount rate on each of them concerning the original discount, then what would be the overall profit or loss percentage on selling a pair of jackets and a T-shirt? (Note: Consider the marked price to be the same as the original marked price.)
    A 25.14% loss Correct Answer Incorrect Answer
    B 35.14% profit Correct Answer Incorrect Answer
    C 33.14% loss Correct Answer Incorrect Answer
    D 45.14% profit Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Selling price of Jackets by Shopkeeper = 0.8 × (a + 300) = Rs. 0.8(a + 300) Selling price of T-Shirt by Shopkeeper = 0.75 × (b + 400) = Rs. 0.75(b + 400) According to question, 0.8(a + 300) + 0.75(b + 400) = 1635 0.8a + 240 + 0.75b + 300 = 1635 0.8a + 0.75b = 1095 -------- (i) Also, (a + b)/2 = 700 (a + b) = 1400 -------- (ii) Solving equation (i), and (ii), we get, a = 900 and b = 500 Therefore, marked price of Jackets = 900 + 300 = Rs. 1200 And, marked price of T-shirt = 500 + 400 = Rs. 900 Cost price of Jackets = 1200/1.2 = Rs.1000 Cost price of T-shirt = 900/1.2 = Rs.750 Total cost price = Rs.1750 Selling price of jackets = 1200 × 0.6 = Rs.720 Selling price of T-shirt = 900 × 0.5 = Rs.450 Total selling price = Rs.1170 Loss percentage = (1750 – 1170) × 100/1170 = 33.14%

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