Question
The population of the town is 10,000. If the male
population increases by 5% and the female population by 10%, the population will become 10,700. How much of the town's present population is female?Solution
Let the number of males =100x And female =100y ATQ- x+y =100     … (1) × 5 5x+10y =700          … (2) 5x+5y =500            … (3) Solving EQ (1) and EQ (2). 5y =200 Y=40. Number of females =100×40 =4000.
More Percentage Questions
26 X √25 + 15 - 80% of 120 = ?2Â
(22.5 × 24) ÷ 40 + 51.50 = ? ÷ 5.25
Simplify the following expression:
84 - [21 - {14 - (25 - 16 + 8) }] ÷ 3 X 6
What value should come in place of (?) question mark in the given expression.
3³ + 4² × 5 − 52 = ?
Simplify the given expression.
666(2/3)% of 30 - 116(2/3)% of 90 =?
25% of 250 + 32% of 200 = ? ÷ √ 16
236.23 - 653.23 + 696.23 = ?
- What will come in place of the question mark (?) in the following questions?
48 + 36 ÷ 6 × 2 = ? 162 ÷ [51 – {29 – (9 – 6̅ ̅+̅ ̅7̅ )}]=?
