The population of the town is 10,000. If the male population increases by 5% and the female population by 10%, the population will become 10,700. How much of the town's present population is female?
Let the number of males =100x And female =100y ATQ- x+y =100 … (1) × 5 5x+10y =700 … (2) 5x+5y =500 … (3) Solving EQ (1) and EQ (2). 5y =200 Y=40. Number of females =100×40 =4000.
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