If x is 80% of y, then what percent of 2x is y?
If x is 80% of y, then what percent of 2x is y? According to question, => x = (80/100)y => y/x = 5/4 => y/2x = 5/8 Required % = [(y/2x) x 100]% => [(5/8) x 100]% = 62.5%
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
I. x2 – 18x + 81 = 0
II. y2 – 3y - 28 = 0
If α, β are the roots of the equation x² – px + q = 0, then the value of α2+β2+2αβ is
...I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
I. x2 – 12x + 32 = 0
II. y2 + y - 20 = 0
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
I. 40x² + 81x + 35 = 0
II. 63y² + 103y + 42 = 0
I. 2p2 - 3p – 2 = 0 II. 2q2 - 11q + 15 = 0
I. 8/(21x) - 2/7 = 0
II. 16y² - 24y +9 = 0
