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Let the number be x. Then, ideally he should have multiplied by x by 5/3. Hence Correct result was`x xx5/3=(5x)/3` By mistake he multiplied x by 3/5 . Hence the result with error =`(3x)/5` Then, error =`(5x)/3-(3x)/5=(16x)/15` Error % =`(Error)/(True Value)xx100=(16/15x)/(5/3x)xx100=64%`
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Options:
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