If A's height is 40% less than that of B, how much percent B's height is more than that of A?
Let Height of B = 100 then Height of A = 100 - 40 = 60 Excess of B's height over A's =(100 - 60)/60 x 100 = 40/60 x100% = 66.66% Alternate Method: If A's height is N% less than that of B, B's height is more than that of A by = N/(100 - N) x 100 = 40/(100 - 40) x100 = 40/60 x 100 = 66.66%
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