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ATQ, Let the total number of boys in class ‘C’ = ‘10a’ Then, the total number of girls in class ‘C’ = 1.25 × 10a = ‘12.5a’ Let the total number of boys in class ‘D’ = ‘10b’ Then, the total number of girls in class ‘D’ = 1.40 × 10b = ‘14b’ According to the question, 10a + 12.5a = 360 Or, 22.5a = 360 Or, a = 360 / 22.5 = 16 And, 10b + 14b = 420 Or, 24b = 420 Or, b = 420 / 24 = 17.5 Required difference = 14b – 12.5a = 14 × 17.5 – 12.5 × 16 = 245 – 200 = 45
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