A number is first increased by 20% and then decreased by 20%. If the net change in the number is 128, then find the original number.
ATQ, Let the original number be '100a'. Final number = 100a x (120/100) x (80/100) = '96a' Net decrease = 100a - 96a = '4a' Or, 4a = 128 Or, 'a' = 128 / 4 = 32 Therefore, required number = 100a = 32 x 100 = 3200
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