ATQ Let the amount of money with Ajay be Rs. '200a' So, the price of 1 apple = (200/80) = Rs. '2.5a' Also, the price of 1 banana = (200/40) = Rs. '5a' ATQ; Amount retained for snacks = 0.05 X 200a = Rs. '10a' Price of 10 bananas = 10 X 5a = Rs. '50a' Remaining amount = 200a - 10a - 50a = Rs. '140a' So, number of apples he can purchase now = (140a/2.5a) = 56 Therefore, required percent = (56/80) X 100 = 70%
I. 3x6- 19x3+16=0
II. 9y4- 27y2+20=0
I. 144x² - 163x - 65 = 0
II. 91y² - 128y -48 = 0
(i) 2x² – x – 3 = 0
(ii) 2y² – 6y + 4 = 0
I. 5x² = 19x – 12
II. 5y² + 11y = 12
I. 99 x² + 31 x – 110 = 0
II. 6y² - 31y + 35 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
I. 2x2- 15x + 25 = 0
II. 3y2- 10y + 8 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. x2 - 11x + 24 = 0
II. y² - 5y + 6 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0