The marks obtained by A is 25% more than B, and the marks obtained by C is 140 more than the difference of the marks obtained by A and B. If C obtained 199 marks, then find the marks obtained by A.
Let the marks obtained by B be ‘x’. So, marks obtained by A = 1.25x According to question, (1.25x – x) + 140 = 199 0.25x = 199 – 140 0.25x = 59 x = 59/0.25 x = 236 Therefore, marks obtained by A = 1.25 × 236 = 295 marks
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