Let the previous price of apple be Rs. '10x' per piece So, new price of the apple = '10x' X 0.7 = Rs. '7x' ATQ: (140/7x) - (140/10x) = 5 or, (20/x) - (14/x) = 5 or, 6/x = 5 or, 5x = 6 x = 1.2 So, previous price of apples = 10 X 1.2 = Rs. 12 per piece
(21 X 5) + ? = (480 - 120) ÷ 3
30% of 60% of 1800 + 13 × 14 = (? ÷ 75) × 5
{(522 – 482 ) ÷ (27 + 73)} × 35 = ?% of 17
[(√576 × √144) ÷ √1296]2 = ? ÷ 3
555.05 + 55.50 + 5.55 + 5 +0.55 = ?
Find the value of 16 X [(8 - 5) of 12 ÷ 4].
(54/6) × 5 + 12 × (17/2) = ?% of 700
(64/25)? × (125/512)?-1 = 5/8
1/6+ 999*53/54 ×9 = ?
(120 × ?)/(36 × 0.2) = 200
