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Let the population of bacteria in the beginning be '100x' So, population at the end of 1st hour = 100x X 2 X 0.6 = '120x' So, population at the end of 2nd hour = 120x X 2 X 0.6 = '144x' So, population at the end of 3rd hour = 144x X 2 X 0.6 = '172.8x' ATQ: 172.8x = 4320 So, x = 25 So, population of the bacteria in the beginning = 100x = 100 X 25 = 2500
The vegetative propagation method that is suitable for the propagation of sapota………………….
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Botanical name of African marigold is -
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