Question
In an exam, two candidates scored 33% and 38% of the
total marks, but both did not pass. The first candidate fell short by 56 marks, while the second candidate was short by 16 marks. Determine the passing marks required for the exam.Solution
Let maximum marks = x According to the questions, x × 33% + 56 = x × 38% + 16 x × 38% - x × 33% = 56 – 16 x × 5% = 40 x = 800 Passing marks = x × 38% + 16 = 800 × 38% + 16 = 304 + 16 = 320
More Percentage Questions
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
I. 6x2 + 23x + 10 = 0
II. 2y2 - 3y - 5 = 0
I. p2 – 2p – 15 = 0
II. q2 + 4q – 12 = 0
Equation 1: x² + 16x + 63 = 0
Equation 2: y² + 10y + 21 = 0
Solve: x² − 7x + 12 = 0
I. 15y2 + 4y – 4 = 0
II. 15x2 + x – 6 = 0
I. x² + 4x + 4 = 0
II. y² - 8y + 16 = 0
I. 18p²- 21p + 6 = 0   Â
II. 16q² - 24q +9 = 0
I. 5x² - 24 x + 28 = 0  Â
II. 4y² - 8 y - 12= 0  Â
If x + 1/x = 3, find x² + 1/x².
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