8 students appear in an examination. In how many ways can the result be announced?
Each students can either pass or fail So there exists two possibilities for each students. So total number of ways = 2⁸ = 256
Statements: F @ R, R $ J, V % J, V # Z
Conclusions: I. F * V II. R * V ...
Statement: L = C; E ≥ M ≥ U ≥ C
Conclusion:
I. E > L
II. E = L
Statement: W>Y<X<Z=U>S; W<T ≥V
I. Y<T
II. X > V
Statements : P > Q < R = U ≤ V = S ≤ W ≥ X > I
Conclusions :
I. Q ≥ V
II. R ≤ W
Statements: A % B & G % B; B # L & J; J @ K # S
Conclusions:
I. L @ K
II. A % K
III. S @ B
...Statements: A > C ≥ B = D; E < F = G < H = I ≤ D
Conclusions:
I. B > E
II. D < E
III. E ≥ B
Statements: J $ K, K * T, T @ N, N © R
Conclusions:
I. J $ T II.R * T ...
Statements: O< V ≤ N = P < S, R = Z ≥ Y = X > O
Conclusions:
I. R > N
II. X > P
III. R > O
Statement:X=Y ≥ Z > Q; Y < V ; W < Q
Conclusions:
I. V > W
II. Q > V
Statements: A & D, D # P, P @ Q, Q % R
Conclusions: I. D & R II. Q # A
...