Question
In a Group of 8 boys and 6 girls, Six children are to be
selected. In how many different ways can they be selected such that at least one boy should be there?Solution
For At least 1 boy we have (1 boy and 5 girls), (2 boys and 4 girls), (3 boys and 3 girls), (4 boys and 2 girls), (5 boys and 1 girl), (6 boys) ∴ Required Number of ways = (8C1 × 6C5) + (8C2 × 6C4) + (8C3 × 6C3) + (8C4 × 6C2) + (8C5 × 6C1) + 8C6 = 48 + 420 + 1120 + 1050 + 336 + 28 = 3002 ways
More Permutation and combination Questions
Evaluate: 25 − 4 × (3 + 2) ÷ 5
What will come in the place of question mark (?) in the given expression?
? ÷ (33 - 12 X 2) = (24 + 50 - 38) ÷ ?Â
12.5% of 384 - 16.66% of 66 = √16 + √? + 22
245 + (45 ÷ 3 + 5) × 6 - 125 = ?
- Evaluate: 168 ÷ 12 × 5 + 190 – 20% of 450
What value should come in the place of (?) in the following questions?
√16 * ? = √144 + (18 * 4 ÷ 3)
1885 ÷ 64.98 + 7.29 + ? = 69.09
What is the value of (152+82) ÷17
- What will come in place of (?), in the given expression.
(81 ÷ 9) + (121 ÷ 11) + (64 ÷ 8) = ? √(24 × 5 ÷ ?) × 4 = 56 + 34 – 10
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