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Number of even places = 4 Number of even digits = 5 (6,6,2,2,2) Number of odd places = 5 Number of odd digits = 4 (5,5,9,9) Since 5 & 9 are repeated two times odd digits can be arranged in 4!/(2!×2! ) = 6 ways Since 6 is repeated two times & 2 is repeated three times even digits can be arranged in 5!/(2! ×3!) = 10 ways Hence, the required number of ways = 6 × 10 = 60 ways.
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