Case I: 4 boys and 3 girls can be selected, Number of ways of selection = 8C4 × 6C3 = 70 × 20 = 1400 Case II: 5 boys and 2 girls can be selected, Number of ways of selection = 8C5 × 6C2 = 56 × 15 = 840 Case III: 6 boys and 1 girl can be selected, Number of ways of selection = 8C6 × 6C1 = 28 × 6 = 168 Case IV: 7 boys can be selected, Number of ways of selection = 8C7 = 8 So, total number of ways of selecting the children = 1400 + 840 + 168 + 8 = 2416 ways
What will come in the place of question mark (?) in the given expression?
{(2/15) + (12/25)} of 375 + 190 = ?% of 375
The value of 3 × 7 + 5 – 6 ÷ 3 – 9 + 45 ÷ 5 × 4 – 45 is:
√ (122 + ? + 65) = 14
(√121 + √196) × 7 =? × 5
(630 ÷ 35) × 2 + 144 = ? × 2
What is the place value of 6 in 367892141?
182 + 10 × 12 - ? = 312