Question
How many numbers of five digits may be formed with the
digits 5, 0, 9, 0, and 6?Solution
³P1 ways and remaining 4 digits 4!/2! (as 0 occurs twice) ways ³P1 × 4!/2! = (3×4×3×2!)/2! = 36 ways
More Permutation and combination Questions
- Which letter and number cluster will replace the question mark (?) to complete the given series?
LT6, KU12, IW24, FZ48, ____ - Which letter-cluster will replace the question mark (?) in the following series?
NPQR, OORQ, PNSP, ____, RLUN - Select the letter-pair that can replace the question mark (?) in the following series?
FK, HM, LQ, RW, ZE, ? - Select the number that can replace the question mark (?) in the following series.
24, 28, 37, 53, 78, ? - A series is given with one term missing. Choose the correct alternatives from the given ones that will complete the series.
57, 59, 56, 61, 54, ___ - Select the number from among the given options that can replace the question mark (?) in the following series.
17, 18, 22, 31, 47, ___ - Which letter-cluster will replace the question mark (?) in the following series?
RGV, UME, ?, AYW, DEF
