Question
There was the leakage in the Oil container. If 10 litre
of oil is leaked out per day then it would have lasted for 25 days and if the leakage was 16 litre per day, then it would have lasted for only 20 days. For how many days would the petrol have lasted if there is no leakage and it was completely used for consumption?Solution
Let x kg of Petrol is used for daily consumption, then (x + 10) × 25 = (x + 16) × 20 25x + 250 = 20x + 320 5x = 70 x = 14 ∴ Total quantity of Oil = (14 + 10) × 25 = 600 litre Required number of Days = 600/14 =300/7 days
If 'a' = √1024 ÷ 4 + 96 ÷ 3 + 85 ÷ 17 and 'b' = 30 × 18 ÷ 6 - 7² + 110, then find the value of (a + b).
... (1782 ÷ 11.98) ÷ 2.92 × 35.89 + 25% of 541 – 67% of 1299 = ?
(2520.33 ÷ 41.67) × (√168.88 + √80.78) - 10% of 1499.85 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
15.232 + 19.98% of 539.99 = ? × 8.99
99% of 4444 + 101% of 6666 =
47.78% of 499.98 + (19.89 × 7.76) = √? × 49.84
The ratio of cost price to the marked price of an article is 5:8. The article had been marked above its cost price by Rs. 270. If the article was sold a...
Find the approximate value of Question mark(?). No need to find the exact value.
(575.86 ÷ 24.03) × (35.96 ÷ 6.03) + √(255.76) = ?
...784.69 + 86.96 ÷ 29.01 = 40.01 + ? + 367.88
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