A cistern has two pipes one can fill it with water in 24 hours and other can empty it in 9 hours. In how many hours will the cistern be emptied if both the pipes are opened together when (5 )/8th of the cistern is already filled with water?
If both pipes are open, then total units per hour empty the tank (A-B) = 3 - 8 = -5 units According to question, Tank has 5/8 of its total capacity in the beginning = 5/8 × 72 = 45 units Time taken to empty the tank = `45/(-5)` = 9 hours
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