Pipe A alone fill the tank in x hours and Pipe B alone fill the tank in (x – 10) hours. If the efficiency of pipe B is triple of pipe A and pipe A fill the tank is 40 liters per hour, then what is the capacity of the tank?
Pipe A alone fill 40 liters per hour, so Pipe B alone fill 120 liters per hour. Capacity of the tank = T => T/40 – T/120 = x – (x – 10) => 3T – T = 1200 => T = 600 liters
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