A boy is supposed to distribute Rs.3600 among his three friends P, Q and R in the ratio of 3:2:5 respectively, but mistakenly he distributed in the ratio of 5:3:2 respectively. Find the difference between amount received by P mistakenly and the amount that P should have actually received.
Amount that should be received by P initially = [3/(3 + 2 + 5)] × 3600 = Rs.1080 Amount received by P mistakenly = [5/(5 + 3 + 2)] × 3600 = Rs.1800 Required difference = 1800 – 1080 = Rs.720
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