Pipe ‘A’ can fill a tank in 10 hours while pipe ‘B’ can empty it in 12 hours. They were operated on alternate hours starting with pipe ‘A’. Find the percentage of tank filled this way in 30 hours.
Let the total capacity of tank be 60 units Efficiency of pipe ‘A’ = 60/10 = 6 units/hour Efficiency of pipe ‘B’ = 60/12 = 5 units/hour Tank filled in 2 hours = (6 – 5) = 1 units Therefore, tank filled in (2 × 15 = 30 hours) = 1 × 15 = 15 units Required percentage of tank filled = (15/60) × 100 = 25%
What should be the minimum number of chocolates so that when distributed among 3,4,5,6 and 7 children, 1,2,3,4 and 5 chocolates are left respectively?
If Ashish has 3 types of pens in a ratio 4 : 6 : 5 such that their LCM is 360, then find the sum of the highest and lowest number of pens that he has?
HCF and LCM of two positive numbers are 24 and 144. If one number is 50% more than the other number, then find the sum of both numbers
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The maximum number of students among whom 891 pens and 810 pencils can be distributed in such a way that each student gets same number of pens and same ...
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The ratio of two numbers is 5:10 and their LCM is 100. The numbers are:
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The HCF of two numbers is 6 and their LCM is 84. If one of these numbers is 42, then the second number is:
Find the LCM of x² – 8x + 15 and x² – 5x + 6 is.
