Question
Pipe ‘A’ can fill a tank in 20 hours while pipe
‘B’ can empty it in 40 hours. They were operated on alternate hours starting with pipe ‘A’. Find the percentage of tank filled this way in 28 hours.Solution
Let the total capacity of tank be 40 units Efficiency of pipe ‘A’ = 40/20 = 2 units/hour Efficiency of pipe ‘B’ = 40/40 = 1 units/hour Tank filled in 2 hours = (2 – 1) = 1 units Therefore, tank filled in (2 × 14 = 28 hours) = 1 × 14 = 14 units Required percentage of tank filled = (14/40) × 100 = 35%
2660.03 ÷ 94.98 x 59.9 = ? + 20.32
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...
Find the approximate value of Question mark(?). No need to find the exact value.
(519.79 ÷ 10.03) × (47.98 ÷ 6) + √(63.94) × 4.04 = ?
...447.79 ÷ √(√2400) + 30.94 × 6.07 – 5.08 × 21.96 = ?
1131.98 + ? – 1125.04 = 1364.93 – 1168.01
11.11% of 1800.89 + 34.89 X 10.99 - 500.50 = ?
(3/7 of 1049.88 + 44.95% of 799.79) ÷ (√168.89 + 24.77% of 400.11) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
If a:(b+c) =3:9 and c:(a+b) =10:14 then find the value of b:(a+c)?
