Pipe ‘A’ can fill a tank in 25 hours while pipe ‘B’ can empty it in 30 hours. They were operated on alternate hours starting with pipe ‘A’. Find the percentage of tank filled this way in 60 hours.
Let the total capacity of tank be 150 units Efficiency of pipe ‘A’ = 150/25 = 6 units/hour Efficiency of pipe ‘B’ = 150/30 = 5 units/hour Tank filled in 2 hours = (6 – 5) = 1 units Therefore, tank filled in (2 × 30 = 60 hours) = 1 × 30 = 30 units Required percentage of tank filled = (30/150) × 100 = 20%
Statements: B < C ≤ D < A ≥ Y
Conclusion: I. A > B II. Y < C
...In which of the following expressions will the expression ‘M ≥ N ' and ‘Q < O’ be definitely true?
Statements: B & C, C # D, D @ E, E % F
Conclusions: I. C & F II. E # B
...Statements:
A ≥ Z > B ≥ Y; C > B ≥ W
Conclusion:
I. A > W
II. C > Y
Statement: L > J ≥ U ≥ F; P < S < L
Conclusion: I. S < F II. P < U
Which of the following symbols should be placed in the blank spaces respectively (in the same order from left to right) in order to complete the given ...
In the following question, a relationship between different elements is shown in the statements, followed by two conclusions I and II. Assuming the stat...
Statement: H > G = M > S; G `>=` T > L; M `<=` F < U
Conclusion: I. F > S II. T < H
...Statements : P > Q < R = U ≤ V = S ≤ W ≥ X > I
Conclusions :
I. Q ≥ V
II. R ≤ W
Statements: M # N # O $ P & Q % R % S
Conclusions : I. Q @ S ...