Question
Tap βAβ and tap βBβ can fill a tank in 42 hours
and 30 hours, respectively. If both taps are opened together, then find the time after which tap βAβ must be closed so the whole tank can be filled in 20 hours.Solution
Let total capacity of the tank is 210 litres (LCM of 42 and 30) Quantity of water filled by tap βAβ in one hour = 210/42 = 5 litres Quantity of water filled by tap βBβ in one hour = 210/30 = 7 litres Let tap βAβ is closed after βxβ hours So, 12 Γ x + 7 Γ (20 β x) = 210 Or, 5x = 70 Or, x = 14 hours
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