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Let total capacity of the tank is 448 litres (LCM of 64 and 56) Quantity of water filled by tap ‘A’ in one hour = 448/64 = 7 litres Quantity of water filled by tap ‘B’ in one hour = 448/56 = 8 litres Let tap ‘A’ is closed after ‘x’ hours So, 15 × x + 8 × (21 – x) = 448 Or, 7x = 280 Or, x = 40 hours
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
{(123 + ? × 28) – 1254} × (2328 ÷ 97 – 13) = 8195
Solve for ?.
?² = 37% of 800 – 14 × 18+ 5! - 20
6612 ÷ 19 - ?% of 240 = -2196
(1/8) × (256 × 2)/(8 × 4) + ?3 = 1730
Simplify the following expression:
84 - [21 - {14 - (25 - 16 + 8) }] ÷ 3 X 6
4? + 82 = 22% of 300
779 + 136 – 334 = 270 + 121 + ?