Question
Tap βAβ and tap βBβ can fill a tank in 40 hours
and 36 hours, respectively. If both taps are opened together, then find the time after which tap βAβ must be closed so the whole tank can be filled in 18 hours.Solution
Let total capacity of the tank is 360 litres (LCM of 40 and 30) Quantity of water filled by tap βAβ in one hour = 360/40 = 9 litres Quantity of water filled by tap βBβ in one hour = 360/36 = 10 litres Let tap βAβ is closed after βxβ hours So, 19 Γ x + 10 Γ (18 β x) = 360 Or, 9x = 180 Or, x = 20 hours
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