📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    ⚡ Month End Offer - Flat 52% Off On All Courses! Enroll Now ⚡
    00:00:00 AM Left

    Question

    Tap ‘A’ and tap ‘B’ can fill a tank in 40 hours

    and 36 hours, respectively. If both taps are opened together, then find the time after which tap ‘A’ must be closed so the whole tank can be filled in 18 hours.
    A 16 hours Correct Answer Incorrect Answer
    B 20 hours Correct Answer Incorrect Answer
    C 24 hours Correct Answer Incorrect Answer
    D 32 hours Correct Answer Incorrect Answer
    E 40 hours Correct Answer Incorrect Answer

    Solution

    Let total capacity of the tank is 360 litres (LCM of 40 and 30) Quantity of water filled by tap ‘A’ in one hour = 360/40 = 9 litres Quantity of water filled by tap ‘B’ in one hour = 360/36 = 10 litres Let tap ‘A’ is closed after ‘x’ hours So, 19 × x + 10 × (18 – x) = 360 Or, 9x = 180 Or, x = 20 hours

    Practice Next
    More Pipes and cisterns Questions

    Relevant for Exams:

    ask-question