Pipe ‘A’ can fill a tank in 20 hours whereas leak ‘A’ can empty it in 30 hours. If they both operate along with pipe ‘B’, then the given tank gets filled in 15 hours. How much time is needed to fill the given tank if pipe ‘B’ and leak ‘A’ work together?
Let the capacity of the tank be 60 litres {LCM (20 and 30)} Efficiency of pipe ‘A’ = 60 ÷ 20 = 3 litres/hour Efficiency of leak ‘A’ = 60 ÷ 30 = 2 litres/hour Combined efficiency of pipe ‘A’ and leak ‘A’ = 3 – 2 = 1 litre/hour Combined efficiency of pipe ‘A’, ‘B’ and leak ‘A’ = 60 ÷ 15 = 4 units/hour Efficiency of pipe ‘B’ = 4 – 1 = 3 units/hour Time taken by pipe ‘B’ and leak ‘A’ to fill the tank = 60 ÷ (3 – 2) = 60 hours
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