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Let the capacity of the tank be 60 litres {LCM (20 and 30)} Efficiency of pipe ‘A’ = 60 ÷ 20 = 3 litres/hour Efficiency of leak ‘A’ = 60 ÷ 30 = 2 litres/hour Combined efficiency of pipe ‘A’ and leak ‘A’ = 3 – 2 = 1 litre/hour Combined efficiency of pipe ‘A’, ‘B’ and leak ‘A’ = 60 ÷ 15 = 4 units/hour Efficiency of pipe ‘B’ = 4 – 1 = 3 units/hour Time taken by pipe ‘B’ and leak ‘A’ to fill the tank = 60 ÷ (3 – 2) = 60 hours
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