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Let the capacity of the cistern = 60 units Then, efficiency of pipe ‘A’ = 60/20 = 3 units/minute Efficiency of pipe ‘B’ = 60/12 = 5 units/minute Efficiency of pipe ‘C’ = 60/10 = 6 units/minute So, combined efficiency of pipes ‘A’, ‘B’ and ‘C’ = 3 + 5 – 6 = 2 units/minute 50% of the cistern’s capacity = 30 units Therefore, time taken by all 3 pipes together to fill 50% of the cistern = 30/2 = 15 minutes
Which number would be at the fourth position from the left end in the last step of the output?
How many steps are required to complete the above arrangement?
How many elements are there between ‘tall’ and ‘75’ in the second last step?
Which of the following would be the last step of the rearrangement?
What is the position of “20” from the right end in the last step?
Which word/number is third to the right of eighth element from right end in step-III?
What is the sum of the third element from the left in step II and second from the right in the last step?
In step III, which of the following element would be at 2nd to the right of 5th from the right end?
If the 9th step of an Input is ‘work in regard to making the district free’ which of the following would be Step IV?
Input for Qs. 6 - 10: 28 33 92 35 73 46 84 11
Which ...