Question
Pipe P can fill a tank in 25 hours and Pipe Q can
emptied it is 30 hours. Pipe P starts filling and they opened for 1 hour each alternatively in what time will the tank be full?Solution
Let the tank capacity be 150 litresĀ (LCM of 25 and 30) So, Pipe P can fill it in 25 hours therefore, Pipe P can fill per hours = 150/25 = 6 litres Pipe Q can emptied it in 30 hours = 150/30 = 5 litres Tank filled after 2 hours = 6 - 5 = 1 litresĀ (If pipes open alternatively) In last hour pipe P fill tank 6 litres So rest part of tank needed to be filled is = 150 - 6 = 144 litres In 2 hours tank filled = 1 litres So, 144 litres to be filled in = 144Ā Ć 2 = 288 therefore, So total time = 288 + 1 = 289 hoursĀ
If 94*6714 is divisible by 11, where * is a digit, then * is equal to
I. 3x2 - 14x + 15 = 0
II. 15 y 2 - 34 y + 15 = 0
I. 2x 2 + 5x + 2 = 0
II. 4 y 2 = 1
In how many ways can the selection of 4 boys and 3 girls can be made from a group of 6 boys and 6 girls?
I. x2 = 100
II. y2 - 9y + 20 = 0
...A shopkeeper fixes the marked price of an item 35% above its cost price. The percentage of discount allowed to gain 8% is
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