Quantity of milk remaining in vessel 'A' after 120 litres of milk is withdrawn = 480 - 120 = 360 litres Ratio of quantity of milk to that of water in vessel 'B' after 120 litres from vessel 'A' is mixed with it = 120:480 = 1:4 So, quantity of water remaining in vessel 'B' after 120 litres of mixture is withdrawn = 480 - {120 X (4/5)} = 384 litres And, quantity of milk in vessel 'A' after 120 litres of mixture is added = 360 + {120 X (1/5)} = 384 litres So, required ratio = 384:384 = 1:1
If x + y + z = 7, x² + y² + z² = 85 and x³ + y³+ z³ = 842, then the value of√3 xyz is:
...Find the value of ‘x’ in the given expression:
(49/16)x× (64/343)x-1= 4/7
if p:q = 3:4 and q:r = 1:2, the find the value of (4p + 3q + r):(2p + 5q - r)
If A = (7)1/3 + (7) -1/3, then the value of {3A3 – 9A} will be:
Calculate the difference between (7.225) 2 - (2.275) 2
(408 × 680)÷(20% of 680) = (250 × 260)÷ 10 + ? – 4500
If (a + b) = 7 and ab = 9, then find the value of (a2 + b2).