Two pipes, A and B, can independently fill the tank in 20 minutes and 30 minutes respectively, while pipe C can empty 12 gallons from the tank in 4 minutes. If all three pipes are operated simultaneously, and they manage to fill the tank in 15 minutes, what is the tank's capacity?
Taking LCM of 20, 30 and 15 = 60 Efficiency of A = 3 Efficiency of B = 2 Efficiency of (A+B-C) = 4 Efficiency of C = (3 + 2) – 4 = -1 Pipe C empty the tank in = 60/1 = 60 min Capacity of the tank = 60 × (12/4) = 180 gallons
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