Question
Tap A can fill a tank in 12 hours. Tap B can fill 12.5%
part of the same tank in 2 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 5/8 part of the tank is filled in 6 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 25% part of the tank?Solution
 Tap A alone can fill the tank in = 12 hours. Tap B alone can fill the tank in = (8/1) × 2 = 16 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 6 × (8/5) = 48/5 Taking LCM of 12, 16 and 48/5 = 48 Efficiency of Tap A = 4 Efficiency of Tap B = 3 Efficiency of Taps (A + B +C) = 5 Efficiency of Taps (A +C) = 5 – 3 = 2 Tap A and C together take to fill 25% part of the tank in, => (25/100) × (48/2) = 6 hours
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