Tap A can fill a tank in 8 hours. Tap B can fill 20% part of the same tank in 4 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 4/7 part of the tank is filled in 8 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 30% part of the tank?
Tap A alone can fill the tank in = 8 hours. Tap B alone can fill the tank in = (5/1) × 4 = 20 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 8 × (7/4) = 14 Taking LCM of 8, 20 and 14 = 280 Efficiency of Tap A = 35 Efficiency of Tap B = 14 Efficiency of Taps (A + B +C) = 20 Efficiency of Taps (A +C) = 20 – 14 = 6 Tap A and C together take to fill 30% part of the tank in, => (30/100) × (280/6) = 14 hours
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